Stellar Motion
Simulation |
(implemented
as a Java applet) |
The Simulator.
The programs and equations are straightforward. They start with N
bodies in 3-dimensional space, and use Newton's laws to determine
the forces on each body due to all other bodies. Then over a
small time increment, each body is displaced by a proper amount.
The increments are chosen quite small. If chosen small enough,
this approach should provide answers arbitrarily close to reality,
assuming "reality" means the motion of point masses under
Newtonian physics.
A Science Fiction Story Using a Stable Lagrange Point.
When I was young (a long time ago), I read a science fiction story by
Isaac Asimov titled "Sucker Bait", first published in 1954. The story mainly
takes place at a binary star system with a single planet at the stable
Lagrange L5 point, which is at the third vertex of a equilateral triangle,
where the stars are at the other two vertices. One star was two-thirds
the mass of the other. It's an entertaining story, with interesting
ideas.
When I wrote the program here, I tested it out with two stars, and
they rotated nicely in ellipses about their common center of gravity.
I tried the stable configurations of two stars with a planet close to
one of them (worked fine), and with a planet at quite a distance from
them both (also worked fine). I also tried 3 stars, 2 in a binary
system and a third coming in from the outside. I had seen an article
describing this motion: usually there is too much energy for the third to be
captured, but instead, sometimes after an incredible amount of chaotic motion,
one of the stars is ejected to infinity, with a binary system remaining.
Any one of the three might be ejected. (See an example
below under "Triple Star Systems".)
Finally, I tried out the system in Asimov's story. At first I used
two stars with equal mass, and a planet with nearly zero mass.
The stars rotated about each other in a perfectly circular orbit.
(This is the red-green circle below.)
I carefully started out the planet at the third vertex of an equilateral triangle,
with the proper vector for its motion.
(This is the blue orbit below. The initial position has the two stars
at opposite ends of a horizontal diameter, with the blue planet at
directly below them at the third vertex of an equilateral triangle.)
It would stay at
the vertex of the triangle for much of one revolution, and then drift into chaos.
I thought that something was wrong with my approach or with my
equations. See Figure 1 for a snapshop of this situation:

Figure 1.
- 2 stars: green and red, of equal mass, each rotating
in the same exact circle about their common center of gravity,
- 1 planet: blue, of negligible mass, starting at the Lagrange
Point, with the proper velocity vector.
- The initial position of the two stars is on the circle at the
center, where the red changes to green. The line through them is
horizontal.
- The initial position of the planet is directly below the stars
at the third vertex of an equilateral angle.
- The planet stays in the L5 position for most of one rotation,
but then it deviates more and more.
- After a chaotic orbit, the planet is eventually ejected to infinity.
- The applet Chaotic orbit gives this behavior.
(Keep pushing the "Go" button.)
The Answer.
Well, a google search under "Lagrange Point" finds the answer almost
immediately. Assuming the third body has negligible mass, the
L5 point is only stable in case the ratio of the masses of
the large bodies is at least 24.96 (exact value:
(25 + sqrt(621))/2 ).
The earth-moon system and the sun-Jupiter both exceed this ratio, and so
they have stable Lagrange Points:
earth mass/moon mass = 5.98 x 1024 kg / 7.35 x 1022 kg = 81.36
sun mass/jupiter mass = 1.989 x 1030 kg / 1.90 x 1027 kg = 1046
The number 24.96 is an interesting dimensionless constant,
a product of basic Newtonian physics.
Going back to my simulation, I couldn't get a stable orbit with the
ratio very close to 25 , but I was able to get
it easily at ratios above 50 .
The earth-moon L4 and L5 points are evidently stable even with perturbations
from the sun and other planets.
With the sun-jupiter system, there are two sets of asteroids in the asteroid belt
(called the trojans)
that move along in the L4 and L5 stable locations, ahead of and behind Jupiter
and moving along with it.
Figure 2 shows a run with two stars having a mass ratio of 100
and a planet with negligible mass at the stable Lagrange Point:

Figure 2.
- 2 stars: green with mass 0.01 and red with mass 1.0.
Red (almost exactly at the center of mass)
is nearly stationary, wobbling and drifting downward very
slowly, while green goes in a circular orbit about red.
- 1 planet: blue, of mass 0.000005, starting at the Lagrange
Point, with the proper velocity vector.
- The arrows show the positions of all three bodies after
about 10 revolutions. They are still in the Lagrange configuration.
- The applet Stable orbit gives this behavior.
(Keep pushing the "Go" button.)
Figure 3 shows a run with a similar configuration, except
that here there are 2 planets (each blue), one in each of the two stable
Lagrange points. Again the 4 arrows show the postions of the two stars and the
two planets after about 12 revolutions.
The applet Stable orbit gives this behavior.

Figure 3.
Many double stars would not have as big a ratio, so their Lagrange points
would not be stable.
All these facts are explained in detail in the following articles:
References about Lagrange points:
Other References:
Back to Asimov's story.
In Asimov's story, the mass ratio of the two stars was assumed
to be 2/3 . In this case, there are L4 and L5
equilibrium points, but they are unstable. Thus with occasional small
orbital corrections, you could keep a space station at that point
indefinitely, but a planet would not stay there. Asimov's
story doesn't work as it is.
It's interesting that as of 2006-09-05, the Wikipedia article
above refers to another article about Asimov's story but does
not say that the configuration in the story is impossible.
Suppose one tries to rescue the story.
One could imagine a binary system with one red star having
0.1 solar masses, and another bright star with
3 solar masses. The mass ratio is 30 ,
so this works. You still have to wonder how the planet got into
position, but in Asimov's story, this was the only such planet
known, so it was presented as very rare. The problem is that
the planet had evolved life. Many people feel that even small
red suns might have planets around them with life, and certainly
the red sun would last long enough for this to happen (such a
small red star lasts much longer than our sun). However
the large star in the system would have a life span
of well under half a billion years -- perhaps not enough time
for life to develop. So in the end, even with the most optimistic
assumptions, it's hard to make Asimov's story work.
Triple Star Systems.
The example below shows a third star entering a binary star system.
Because of the large amount of energy in the system, capture
is difficult, and the usual outcome is for one star to be
ejected to infinity, leaving a new binary system.

Figure 4.
- 3 stars: Green, Red, and Blue, of equal mass.
- Red and Green form a binary system, while Blue is an
interloper, coming in from the upper right.
- After a chaotic interaction, Green is ejected off to the left, while
Blue and Red form a new binary system that leaves at the bottom.
- The applet Chaotic interaction of 3 stars gives this behavior.

Figure 5.
Very similar to Figure 4.
- 3 stars: Green, Red, and Blue, of equal mass.
- Red and Green form a binary system, originally coming from
the middle, moving right and upward.
- Blue is an interloper, coming in from the upper right.
- First Red is thrown into a small orbit (toward the upper left),
while Blue and Green rotate about one another (toward the lower right).
- Then Blue is thrown out into a larger orbit (straight down),
while Red and Green rotate about one another (toward the top).
- Finally, Green is ejected to infinity off to the upper right, while
Blue and Red form a new binary system that leaves toward the lower left.

Figure 6.
- Red and Green have mass 1 ,
while Blue has mass 0.1 .
- Blue starts at the unstable Lagrange L5 point, with the
correct initial velocity.
- Blue stays at the Lagrange L5 point for most of one
revolution, and then drifts off.
- Blue goes through a chaotic orbit, and affects the
orbits of Red and Green somewhat, even with its small mass.
- Finally, Blue is ejected to infinity (upward),
and Red and Green continue toward the left without Blue.